Simple addition program in bash




















Here, 10 is assigned to the variable, n. Different types of logical conditions can be used in if statement with two or more conditions. How you can define multiple conditions in if statement using AND logic is shown in the following example. Here, the value of n will be taken from the user. The use of else if condition is little different in bash than other programming language.

Case statement is used as the alternative of if-elseif-else statement. The output of the following script will be same to the previous else if example. Bash script can read input from command line argument like other programming language.

Two argument values read by the following script and prints the total number of arguments and the argument values as output. How you can read command line arguments with names is shown in the following script. Here, two arguments, X and Y are read by this script and print the sum of X and Y. You can easily combine string variables in bash.

Like other programming language, bash has no built-in function to cut value from any string data. But you can do the task of substring in another way in bash that is shown in the following script.

Here, the value, 6 indicates the starting point from where the substring will start and 5 indicates the length of the substring. You can do the arithmetical operations in bash in different ways. How you can add two integer numbers in bash using double brackets is shown in the following script. Two integer values will be taken from the user and printed the result of addition.

How you can create a simple function and call the function is shown in the following script. How are we doing? Please help us improve Stack Overflow. Take our short survey. Stack Overflow for Teams — Collaborate and share knowledge with a private group. Create a free Team What is Teams?

Collectives on Stack Overflow. Learn more. How to write addtion program in unix [duplicate] Ask Question. Asked 8 years, 3 months ago. Active 8 years, 1 month ago. What you posted isn't valid perl, it's not valid sh either. Please edit it to match exactly what you have. Looks like you need to get a tutorial on shell scripting. You don't know the very basics, and SO is not a tutoring service. I strongly suspect that your output is not the result of the script code you posted above - that script would not run for a number of different reasons, and even if it did, it's not doing what you think it is Add a comment.

Active Oldest Votes. Note the use of just one, double-quoted string with an embedded variable reference. Improve this answer. Ah, yeah Alexej Magura Alexej Magura 3, 3 3 gold badges 23 23 silver badges 39 39 bronze badges.

Helpful; observations in addition to l0b0's valid point: the --var line results in 1 , not 2. Chris Seymour Dheeraj R Dheeraj R 9 9 silver badges 17 17 bronze badges. Sign up or log in Sign up using Google.



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